differential operators
Kai Ludwig
kai.ludwig at uni-tuebingen.de
Thu Nov 20 18:08:50 CET 2003
Christian Bauer wrote:
> Hi!
>
> On Tue, Nov 18, 2003 at 06:20:30PM +0100, Kai Ludwig wrote:
>
>>dF/du = du/du * du/dx + u * d/du du/dx
>>
>>thus, formally
>>
>>dF/du = du/dx + u * d/dx
>
>
> Here's something hacked together that achieves the desired effect for
> GiNaC 1.2 (treating the dx like a function):
>
> const unsigned TINFO_differential = 0x42420001U;
>
> DECLARE_FUNCTION_1P(dx)
>
> // this is ad-hockery...
> static ex dx_deriv(const ex & a, unsigned diff_param) { return dx(1); }
>
> REGISTER_FUNCTION(dx,
> derivative_func(dx_deriv).
> set_return_type(return_types::noncommutative, TINFO_differential))
>
> int main()
> {
> symbol u("u", return_types::noncommutative, TINFO_differential);
> ex F = u * dx(u);
>
> cout << F << endl;
> // "u*dx(u)"
> cout << F.diff(u) << endl;
> // "u*dx(1)+dx(u)"
> }
>
> But I don't know if that's general enough for what you have in mind.
>
> Bye,
> Christian
>
Danke ;-)
I plan to use GiNaC in a few months within our project...
Maybe then I can send you results/questions_hope_not
Kai
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