[GiNaC-list] Converting an expression to std::string and back again

[Robert Hai]

Awesome ! That works ! Do you have an idea on how to convert the ex returned by diff back to a std::string ?
 
 

Gesendet: Dienstag, 28. März 2017 um 22:49 Uhr
Von: "Richard B. Kreckel" <kreckel at in.terlu.de>
An: ginac-list at ginac.de
Betreff: Re: [GiNaC-list] Converting an expression to std::string and back again
On 03/28/2017 09:57 AM, Robert Hai wrote:
> for a project I need to convert a std::string to an ex, diff it and then convert it back to a std::string. For the conversion from std::string to ex I found this constructor :
>
> /** Construct example from string and a list of symbols. The input grammar is * similar to the GiNaC
> output format. All symbols and indices to be used * in the expression must be specified in a lst in the
> second argument. * Undefined symbols and other parser errors will throw an exception. */
> ex(const std::string &s, const ex &l);
>
> at http://www.ginac.de/reference/classGiNaC_1_1ex.html#ace68037326c1a2b8c93a56716599ec7a
>
> So I tried doing the following :
>
> symbol x("x");
> ex expression;
> ex e("x^2",expression);
> std::cout << diff(e,x) << std::endl;
>
> But this leads me to this exception :
>
> std::invalid_argument: find_or_insert_symbol: symbol "x" not found
>
> Note that I tried using expression and e in diff(e,x). Unfortunately I could not find any documentation on how to convert the expression diff returns to a std::string.

The second argument should be a GiNaC::lst with all symbols that occur
in the string. Try this:

symbol x("x");
lst syms = {x};
ex e("x^2", syms);
std::cout << diff(e, x) << std::endl;
// -> 2*x

All my best,
-richy.
--
Richard B. Kreckel
<http://in.terlu.de/~kreckel/[http://in.terlu.de/~kreckel/]>
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