> If a series A starts with x^n, then the series 1/A *ends*, not starts, > with 1/x^n. OK, sorry, that's not corect. Let me say it differently: series(sin(x)-x, x, 2) == Order(x^2) This does not mean 1/series(sin(x)-x, x, 2) == Order(x^-2), because series(1/(sin(x)-x), x, -2) == -6/x^3 + Order(x^-2)