* tests on these numbers like is_integer() etc... */
/*
- * GiNaC Copyright (C) 1999-2000 Johannes Gutenberg University Mainz, Germany
+ * GiNaC Copyright (C) 1999-2007 Johannes Gutenberg University Mainz, Germany
*
* This program is free software; you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
*
* You should have received a copy of the GNU General Public License
* along with this program; if not, write to the Free Software
- * Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
+ * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
*/
-#include "exams.h"
+#include <iostream>
+#include <sstream>
+#include "ginac.h"
+using namespace std;
+using namespace GiNaC;
+
/* Simple and maybe somewhat pointless consistency tests of assorted tests and
* conversions. */
-static unsigned exam_numeric1(void)
+static unsigned exam_numeric1()
{
unsigned result = 0;
numeric test_int1(42);
if (!test_int1.is_integer()) {
clog << test_int1
- << " erroneously not recognized as integer" << endl;
+ << " erroneously not recognized as integer" << endl;
++result;
}
if (!test_int1.is_rational()) {
clog << test_int1
- << " erroneously not recognized as rational" << endl;
+ << " erroneously not recognized as rational" << endl;
++result;
}
if (!test_rat1.is_rational()) {
clog << test_rat1
- << " erroneously not recognized as rational" << endl;
+ << " erroneously not recognized as rational" << endl;
++result;
}
if (test_rat1.is_integer()) {
if (!test_crat.is_crational()) {
clog << test_crat
- << " erroneously not recognized as complex rational" << endl;
+ << " erroneously not recognized as complex rational" << endl;
++result;
}
int i = numeric(1984).to_int();
if (i-1984) {
clog << "conversion of " << i
- << " from numeric to int failed" << endl;
+ << " from numeric to int failed" << endl;
++result;
}
e1 = test_int1;
if (!e1.info(info_flags::posint)) {
clog << "expression " << e1
- << " erroneously not recognized as positive integer" << endl;
+ << " erroneously not recognized as positive integer" << endl;
++result;
}
e2 = test_int1 + a;
- if (ex_to_numeric(e2).is_integer()) {
+ if (e2.info(info_flags::integer)) {
clog << "expression " << e2
- << " erroneously recognized as integer" << endl;
+ << " erroneously recognized as integer" << endl;
++result;
}
test_rat1 += test_rat1;
if (!test_rat1.is_integer()) {
clog << "3/2 + 3/2 erroneously not integer 3 but instead "
- << test_rat1 << endl;
+ << test_rat1 << endl;
++result;
}
test_rat1 = numeric(3)/numeric(2);
test_rat2 -= test_rat1; // 1
if (!test_rat2.is_integer()) {
clog << "5/2 - 3/2 erroneously not integer 1 but instead "
- << test_rat2 << endl;
+ << test_rat2 << endl;
++result;
}
* Implementing a workaround sadly introduced another bug on May 28th 1999
* that was fixed on May 31st. The workaround turned out to be stupid and
* the original bug in CLN was finally killed on September 2nd. */
-static unsigned exam_numeric2(void)
+static unsigned exam_numeric2()
{
unsigned result = 0;
/* Assorted tests to ensure some crucial functions behave exactly as specified
* in the documentation. */
-static unsigned exam_numeric3(void)
+static unsigned exam_numeric3()
{
unsigned result = 0;
numeric calc_rem, calc_quo;
a = 23; b = 4; calc_rem = irem(a, b);
if (calc_rem != 3) {
clog << "irem(" << a << "," << b << ") erroneously returned "
- << calc_rem << endl;
+ << calc_rem << endl;
++result;
}
a = 23; b = -4; calc_rem = irem(a, b);
a = -23; b = 4; calc_rem = irem(a, b);
if (calc_rem != -3) {
clog << "irem(" << a << "," << b << ") erroneously returned "
- << calc_rem << endl;
+ << calc_rem << endl;
++result;
}
a = -23; b = -4; calc_rem = irem(a, b);
if (calc_rem != -3) {
clog << "irem(" << a << "," << b << ") erroneously returned "
- << calc_rem << endl;
+ << calc_rem << endl;
++result;
}
// and now the overloaded irem(a,b,q):
a = 23; b = 4; calc_rem = irem(a, b, calc_quo);
if (calc_rem != 3 || calc_quo != 5) {
clog << "irem(" << a << "," << b << ",q) erroneously returned "
- << calc_rem << " with q=" << calc_quo << endl;
+ << calc_rem << " with q=" << calc_quo << endl;
++result;
}
a = 23; b = -4; calc_rem = irem(a, b, calc_quo);
if (calc_rem != 3 || calc_quo != -5) {
clog << "irem(" << a << "," << b << ",q) erroneously returned "
- << calc_rem << " with q=" << calc_quo << endl;
+ << calc_rem << " with q=" << calc_quo << endl;
++result;
}
a = -23; b = 4; calc_rem = irem(a, b, calc_quo);
if (calc_rem != -3 || calc_quo != -5) {
clog << "irem(" << a << "," << b << ",q) erroneously returned "
- << calc_rem << " with q=" << calc_quo << endl;
+ << calc_rem << " with q=" << calc_quo << endl;
++result;
}
a = -23; b = -4; calc_rem = irem(a, b, calc_quo);
if (calc_rem != -3 || calc_quo != 5) {
clog << "irem(" << a << "," << b << ",q) erroneously returned "
- << calc_rem << " with q=" << calc_quo << endl;
+ << calc_rem << " with q=" << calc_quo << endl;
++result;
}
// check if iquo(a, b) and iquo(a, b, r) really behave like Maple's
a = 23; b = 4; calc_quo = iquo(a, b);
if (calc_quo != 5) {
clog << "iquo(" << a << "," << b << ") erroneously returned "
- << calc_quo << endl;
+ << calc_quo << endl;
++result;
}
a = 23; b = -4; calc_quo = iquo(a, b);
if (calc_quo != -5) {
clog << "iquo(" << a << "," << b << ") erroneously returned "
- << calc_quo << endl;
+ << calc_quo << endl;
++result;
}
a = -23; b = 4; calc_quo = iquo(a, b);
if (calc_quo != -5) {
clog << "iquo(" << a << "," << b << ") erroneously returned "
- << calc_quo << endl;
+ << calc_quo << endl;
++result;
}
a = -23; b = -4; calc_quo = iquo(a, b);
if (calc_quo != 5) {
clog << "iquo(" << a << "," << b << ") erroneously returned "
- << calc_quo << endl;
+ << calc_quo << endl;
++result;
}
// and now the overloaded iquo(a,b,r):
a = 23; b = 4; calc_quo = iquo(a, b, calc_rem);
if (calc_quo != 5 || calc_rem != 3) {
clog << "iquo(" << a << "," << b << ",r) erroneously returned "
- << calc_quo << " with r=" << calc_rem << endl;
+ << calc_quo << " with r=" << calc_rem << endl;
++result;
}
a = 23; b = -4; calc_quo = iquo(a, b, calc_rem);
if (calc_quo != -5 || calc_rem != 3) {
clog << "iquo(" << a << "," << b << ",r) erroneously returned "
- << calc_quo << " with r=" << calc_rem << endl;
+ << calc_quo << " with r=" << calc_rem << endl;
++result;
}
a = -23; b = 4; calc_quo = iquo(a, b, calc_rem);
if (calc_quo != -5 || calc_rem != -3) {
clog << "iquo(" << a << "," << b << ",r) erroneously returned "
- << calc_quo << " with r=" << calc_rem << endl;
+ << calc_quo << " with r=" << calc_rem << endl;
++result;
}
a = -23; b = -4; calc_quo = iquo(a, b, calc_rem);
if (calc_quo != 5 || calc_rem != -3) {
clog << "iquo(" << a << "," << b << ",r) erroneously returned "
- << calc_quo << " with r=" << calc_rem << endl;
+ << calc_quo << " with r=" << calc_rem << endl;
++result;
}
/* Now we perform some less trivial checks about several functions which should
* return exact numbers if possible. */
-static unsigned exam_numeric4(void)
+static unsigned exam_numeric4()
{
unsigned result = 0;
bool passed;
// square roots of squares of integers:
passed = true;
- for (int i=0; i<42; ++i) {
- if (!sqrt(numeric(i*i)).is_integer()) {
+ for (int i=0; i<42; ++i)
+ if (!sqrt(numeric(i*i)).is_integer())
passed = false;
- }
- }
if (!passed) {
clog << "One or more square roots of squares of integers did not return exact integers" << endl;
++result;
// square roots of squares of rationals:
passed = true;
- for (int num=0; num<41; ++num) {
- for (int den=1; den<42; ++den) {
- if (!sqrt(numeric(num*num)/numeric(den*den)).is_rational()) {
+ for (int num=0; num<41; ++num)
+ for (int den=1; den<42; ++den)
+ if (!sqrt(numeric(num*num)/numeric(den*den)).is_rational())
passed = false;
- }
- }
- }
if (!passed) {
clog << "One or more square roots of squares of rationals did not return exact integers" << endl;
++result;
/* This test examines that simplifications of the form 5^(3/2) -> 5*5^(1/2)
* are carried out properly. */
-static unsigned exam_numeric5(void)
+static unsigned exam_numeric5()
{
unsigned result = 0;
ex e2 = expand(e1 - 10 + 5*pow(3,numeric(3,5)));
if (!e2.is_zero()) {
clog << "expand((1+3^(1/5)-3^(2/5))^3-10+5*3^(3/5)) returned "
- << e2 << " instead of 0." << endl;
+ << e2 << " instead of 0." << endl;
++result;
}
return result;
}
-unsigned exam_numeric(void)
+/* This test checks whether the numeric output/parsing routines are
+ consistent. */
+static unsigned exam_numeric6()
+{
+ unsigned result = 0;
+
+ symbol sym("sym");
+ vector<ex> test_numbers;
+ test_numbers.push_back(numeric(0)); // zero
+ test_numbers.push_back(numeric(1)); // one
+ test_numbers.push_back(numeric(-1)); // minus one
+ test_numbers.push_back(numeric(42)); // positive integer
+ test_numbers.push_back(numeric(-42)); // negative integer
+ test_numbers.push_back(numeric(14,3)); // positive rational
+ test_numbers.push_back(numeric(-14,3)); // negative rational
+ test_numbers.push_back(numeric(3.141)); // positive decimal
+ test_numbers.push_back(numeric(-3.141)); // negative decimal
+ test_numbers.push_back(numeric(0.1974)); // positive decimal, leading zero
+ test_numbers.push_back(numeric(-0.1974)); // negative decimal, leading zero
+ test_numbers.push_back(sym); // symbol
+
+ for (vector<ex>::const_iterator br=test_numbers.begin(); br<test_numbers.end(); ++br) {
+ for (vector<ex>::const_iterator bi=test_numbers.begin(); bi<test_numbers.end(); ++bi) {
+
+ for (vector<ex>::const_iterator er=test_numbers.begin(); er<test_numbers.end(); ++er) {
+ for (vector<ex>::const_iterator ei=test_numbers.begin(); ei<test_numbers.end(); ++ei) {
+
+ // Construct expression, don't test invalid ones
+ ex base = (*br) + (*bi)*I, exponent = (*er) + (*ei)*I, x;
+ try {
+ x = pow(base, exponent);
+ } catch (...) {
+ continue;
+ }
+
+ // Print to string
+ std::ostringstream s;
+ s << x;
+
+ // Read back expression from string
+ string x_as_string = s.str();
+ ex x_again(x_as_string, lst(sym));
+
+ // They should be equal
+ if (!x_again.is_equal(x)) {
+ clog << x << " was read back as " << x_again << endl;
+ ++result;
+ }
+ }
+ }
+ }
+ }
+
+ return result;
+}
+
+unsigned exam_numeric()
{
unsigned result = 0;
cout << "examining consistency of numeric types" << flush;
- clog << "----------consistency of numeric types:" << endl;
result += exam_numeric1(); cout << '.' << flush;
result += exam_numeric2(); cout << '.' << flush;
result += exam_numeric3(); cout << '.' << flush;
result += exam_numeric4(); cout << '.' << flush;
result += exam_numeric5(); cout << '.' << flush;
-
- if (!result) {
- cout << " passed " << endl;
- clog << "(no output)" << endl;
- } else {
- cout << " failed " << endl;
- }
+ result += exam_numeric6(); cout << '.' << flush;
return result;
}
+
+int main(int argc, char** argv)
+{
+ return exam_numeric();
+}