[CLN-list] Operations with different precisions
Sebastian Macke
macke at mf.mpg.de
Mon Oct 12 18:11:30 CEST 2009
Hi,
following code snippet
cln::cl_F x = cl_float(0.5, cln::float_format(50));
x = cos(x);
cout << "\n" << x << "\n";
x = x + cln::cl_F(1.);
cout << x << "\n";
gives the output
0.8775825618903727161162815826038296519916451971097440529976L0
1.8775825618903728d0
Is there a feature that the float with the highest precision
is used as the result precision?
Thanks
Sebastian
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