[CLN-list] Operations with different precisions

[Richard B. Kreckel]

Hi,

Sebastian Macke wrote:
> following code snippet
> 
>  cln::cl_F x = cl_float(0.5, cln::float_format(50));
>  x = cos(x);
>  cout << "\n" << x << "\n";
>  x = x + cln::cl_F(1.);
>  cout << x << "\n";
> 
> gives the output
> 
>  0.8775825618903727161162815826038296519916451971097440529976L0
>  1.8775825618903728d0
> 
> Is there a feature that the float with the highest precision
> is used as the result precision?

I suppose a typo: Of course, in operators taking two floats, the 
precision of the float with the *least* precision is used as the result 
precision.

Regards
    -richy.
-- 
Richard B. Kreckel
<http://www.ginac.de/~kreckel/>