[GiNaC-list] Equal indexed expressions
Vladimir Kisil
kisilv at maths.leeds.ac.uk
Mon Apr 25 20:04:29 CEST 2005
Dear Alexei,
Thanks for the explanations. I added to your code just two lines
at the end:
#include <iostream>
#include <ginac/ginac.h>
using namespace std;
using namespace GiNaC;
int main(int argc, char** argv)
{
varidx i(symbol("i"), 2);
varidx j(symbol("j"), 2);
matrix mink2_matr(2, 2, lst(-1, 0, 0, 1));
matrix a(1, 2, lst(symbol("a0"), symbol("a1")));
ex test1 = indexed(mink2_matr, i, i)*indexed(a, i);
ex test2 = indexed(mink2_matr, j.toggle_variance(), i)*indexed(a, j);
cout << test1 << " = " << test1.simplify_indexed() << endl;
cout << test2 << " = " << test2.simplify_indexed() << endl;
cout << "test1 substituted = " << test1.simplify_indexed().subs(i == varidx(0, 2)) << endl;
cout << "test2 substituted = " << test2.simplify_indexed().subs(i == varidx(0, 2)) << endl;
return 0;
}
and the output now becomes:
[[a0,a1]]~i*[[-1,0],[0,1]]~i~i = [[a0,a1]]~i*[[-1,0],[0,1]]~i~i
[[a0,a1]]~j*[[-1,0],[0,1]].j~i = [[-a0,a1]]~i
test1 substituted = -a0
test2 substituted = -a0
i.e., the initial difference between objects disappeared after the
substitution was made. Should it be classified as a bug? I would
prefer if not all objects with indexes in GiNaC will be necessarily a
tensors.
I had already a code which expand dummy-index summations in order to
see "equality" (in non-tensor sense) similar to above, but I wish to
check, that this cannot be already done by some standard tools.
Thanks,
Vladimir
--
Vladimir V. Kisil email: kisilv at maths.leeds.ac.uk
-- www: http://maths.leeds.ac.uk/~kisilv/
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